锘縎qliteQuery:选择b.Name作为标题,b.ID_NUM作为ID from yb_dir as a LEFT JOIN yb_fenlei as b ON a.fenleid=b.ID_NUM,其中a.PID=按b.Name分组
SqliteError:不是错误
SQLiterRNO:1
消息:靠近“GROUP”:语法错误